Gen Chem · Sem 1 · 2-7b
Mole Conversions

Follow the map, and cancel the units.

In the lab, scales read in grams, but chemical equations "speak" in moles. How do we convert back and forth between what we can weigh and what the atoms require? We use a simple conversion map, and the foolproof method of dimensional analysis. If you set up the fractions so that the units cancel, the math will balance itself.

Alignment
HS-PS1-7 Convert between mass (grams) and moles using dimensional analysis (PS1-7.2 target).
Objective
Set up conversion factors to translate between mass and moles, track unit cancelation, and explain calculations.
Scope
Gram-to-mole and mole-to-gram conversions. Molar mass as a fractional conversion factor. (Empirical formulas are excluded).

Core Claims

  • Dimensional Analysis: Fractions containing equivalent values in different units are used to safely multiply and convert.
  • Diagonal Cancellation: Conversion grids are set up so that the starting unit cancels out diagonally, leaving the desired target unit.
  • Conversion Values: Molar Mass (grams/mol) is used to convert grams ↔ moles. Avogadro's number is used to convert moles ↔ particle counts.

Dimensional Analysis Setup

g starting 1 mol Molar Mass (g)

Retrieval Checklist

  • Set up dimensional analysis grids with matching units.
  • Convert mass to moles, and moles to particle counts.

Mole is always the central hub.

To convert chemical quantities in the laboratory, you must follow one golden rule: always convert through the mole. The mole is the common counting language of chemistry, connecting the microscopic count to the macroscopic weight.

This relationship forms our Mole Map. If you start with a mass in grams and want to find moles, or if you start with moles and want to find mass, the molar mass is the conversion factor bridge.

Grams (g) Moles (mol) ÷ molar mass 36.04 g H₂O (bulk water) ÷ 18.02 g/mol 2.00 mol H₂O (counted groups)
Start in grams, the unit you actually weigh. Dividing by molar mass converts to moles.
Grams (g) Moles (mol) ÷ molar mass × molar mass 146.10 g NaCl (weighed bulk) × 58.44 g/mol 2.50 mol NaCl (crystal lattice)
The bridge runs both ways: multiplying moles by molar mass gets you back to grams.
Grams (g) Moles (mol) Particles (atoms, molecules) × 6.022×10²³ 2.00 mol CO₂ (chemical quantity) × 6.022×10²³ CO₂ 1.204×10²⁴ molecules (individual count)
Moles are also the hub for counting: multiply by Avogadro's number (6.022×10²³) to reach individual particles.
Grams (g) Moles (mol) Particles (atoms, molecules) ÷ molar mass × molar mass × 6.022×10²³ ÷ 6.022×10²³ 36.04 g H₂O (Grams) The Mole (mol) Counted groups of units CO₂ molecule (Particles)
The complete map. Moles sit at the hub — you never convert grams directly to particles, you always pass through moles.

This lesson focuses on the grams ↔ moles spoke. The moles ↔ particles spoke uses the same logic with Avogadro's number (6.022 × 10²³) in place of molar mass — you met it back in 2-7a, and it's on the map here as a reminder that the mole is always the hub, never a detour through grams.

Let the units do the work.

Rather than memorizing when to multiply or divide, we use dimensional analysis (the factor-label method). You treat units like algebraic variables: any unit in a numerator divided by the same unit in a denominator cancels out, leaving only the desired unit behind.

A conversion factor is written as a fraction. Because one mole of Water (H₂O) is exactly equal to 18.02 grams, we can write two conversion factor fractions that both equal 1:

1 mol H₂O18.02 g H₂O      or      18.02 g H₂O1 mol H₂O

To convert 36.04 grams of water to moles, you choose the fraction that puts the unwanted unit (grams) in the denominator to cancel the starting grams:

36.04 g H₂O × 1 mol H₂O18.02 g H₂O = 2.00 mol H₂O

Because the starting unit (g H₂O) and the denominator unit cancel, you are left with `mol H₂O`. The units prove that the setup is correct before you ever punch the numbers into a calculator.

Set up the math. Watch the units cancel.

Select the conversion factor card that correctly cancels the starting unit. Drag or click the card to slot it in, and check if the math balances.

Dimensional Analysis · Unit Solver Problem 1 of 5

Loading problem...

36.04 g H₂O
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Click a card below to slot it here
=
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Available Conversion Factors
Visual Conversion Path
Analysis Dashboard

Awaiting setup...

Click one of the cards below to choose a conversion factor. Look for the card that puts the starting unit in the denominator so they cancel out.

Predict the scale outcome.

1. Mass of 2.50 moles of water: One mole of water has a mass of 18.02 grams. If you measure out exactly 2.50 moles of water, what will the scale read?

The Answer: 45.05 grams

To convert moles to grams, you multiply by the molar mass:
2.50 mol H₂O × (18.02 g H₂O / 1 mol H₂O) = 45.05 g H₂O
The moles units cancel out, leaving grams.

2. Moles in a carbon sample: A sample of pure charcoal contains 36.03 grams of Carbon (molar mass 12.01 g/mol). How many moles of Carbon atoms are in this sample?

The Answer: 3.00 moles

To convert grams to moles, you divide by the molar mass:
36.03 g Carbon × (1 mol Carbon / 12.01 g Carbon) = 3.00 mol Carbon
The grams units cancel, leaving moles.

Say it back.

Fill in the blanks to lock in the core terms. Matches are case-insensitive.

Vocabulary Check

Fill in the conversion terms.

Why do we cancel units?

Explain how treating units as algebraic variables guarantees that you don't accidentally multiply when you should divide during mole conversions.

Model Answer

Treating units as algebraic variables ensures that you place the conversion units in the correct positions (numerator or denominator) so that unwanted units cancel out. If you set up a conversion incorrectly—for example, multiplying grams by grams/mole instead of mole/grams—the units will not cancel and will instead result in a nonsense unit (like g²/mol). Tracking unit cancelation mathematically guarantees that the final remaining unit is the one you are solving for, preventing calculation direction errors.

Solve with dimensional analysis.

Give yourself a point for each idea you actually wrote down. The flag (⚑) marks the critical unit tracking step.

Gen Chem · HS-PS1-7 · constructed response [3 marks]

A recipe requires exactly 126.02 grams of sodium bicarbonate (NaHCO3, molar mass 84.01 g/mol). Calculate the moles of NaHCO3 required, showing your complete dimensional analysis setup with all conversion units and unit cancelations clearly written out.

Mark Scheme — 3 marks
  • Writes the starting value with units (126.02 g NaHCO₃).
  • Shows the conversion factor set up with grams in the denominator (× 1 mol NaHCO₃ / 84.01 g NaHCO₃), showing the cancelation of the grams units. (⚑ This dimensional analysis unit layout is required for full credit.)
  • Calculates the correct final value with proper units: 1.500 moles of NaHCO₃ (accept 1.500 mol or 1.50 mol NaHCO₃).

Self-score: 3 = all three points · 2 = calculated 1.5 mol but missing unit cancelation marks in setup · 1 = calculated 1.5 mol with no setup shown.

Why This Matters

Carbon capture engineering requires precise molar scaling. Industrial scrubbers capture carbon dioxide from exhaust gas. Chemical engineers must use factor-label conversions to calculate the exact mass of liquid amine required in grams to absorb the targeted number of gaseous CO₂ molecules.