Gen Chem · Sem 1 · 1-2b
Molecular Polarity

Two polar bonds. One nonpolar molecule, one wildly polar one.

CO2 has two polar bonds and is a nonpolar molecule. Water has two polar bonds and is one of the most polar molecules there is. Same ingredient, opposite result — the difference is shape. By the end of this page you'll be able to take any molecule's bonds and shape and predict whether it's polar, and which intermolecular force that unlocks.

Alignment
HS-PS1-2Explain chemical outcomes based on the outermost electron states and periodic trends. (Sub-target PS1-2.1: bond and molecular polarity from electronegativity and structure.)
Objective
Combine bond polarity (ΔEN) with a molecule's given shape to decide molecular polarity, then predict which intermolecular force that molecule can access.
Scope
Shapes are shown as given fact — linear, bent, pyramidal, symmetric. No VSEPR, no angle derivation, no naming the theory behind why a shape is what it is.
O C O δ+ δ− δ− O H H δ− δ+ δ+
every C=O and O–H bond here is polar — δ+ and δ− mark which end
O C O δ+ δ− δ− O H H δ− δ+ δ+
each dipole vector points from δ+ toward δ− — one vector per bond
O C O δ+ δ− δ− net dipole = 0 O H H δ− δ+ δ+ net dipole ≠ 0 · points toward O
same polar bonds · different geometry · different molecular polarity

Core Claims

  • Molecular Polarity: Depends on both bond polarity (ΔEN) and molecular shape.
  • Symmetry & Cancellation: Symmetric shapes (like linear CO2) allow polar bond dipoles to pull in equal and opposite directions and cancel out, leaving the molecule nonpolar.
  • Asymmetry & Reinforcement: Asymmetric shapes (like bent H2O) cause dipoles to reinforce, creating a net dipole and a polar molecule.

Dipole Cancellation vs. Reinforcement

CO₂ (Linear) Net Dipole = 0 H₂O (Bent) Net Dipole ≠ 0

Retrieval Checklist

  • Draw vectors representing bond dipoles.
  • Determine if molecular geometry cancels or reinforces dipoles.
  • Predict whether a molecule is polar or nonpolar.

"The bonds are polar, so the molecule is polar." Sometimes.

Here's a trap worth naming before you fall into it: the bonds are polar, so the molecule is polar. Sometimes. Electronegativity difference (ΔEN) tells you whether a single bond dipole exists — one tug-of-war, judged bond by bond. Molecular polarity asks a different question: do all of a molecule's tugs-of-war add up to a net pull across the whole thing? Pulls in opposite directions cancel. Pulls in the same general direction don't.

CO2 is the clean case. Each C=O bond really is polar — oxygen wins the tug-of-war, so oxygen ends up δ− and carbon δ+. But CO2 is a straight line, and the two oxygens sit on exactly opposite sides of carbon. Their pulls point in exactly opposite directions and cancel — not approximately, exactly. Nonpolar molecule, polar bonds and all.

Water refuses to line up the same way. Its two O–H bonds sit at about 104° to each other — bent, not straight. Both pulls point generally toward oxygen, so instead of canceling they gang up into a net dipole. The oxygen end of the molecule runs δ−, the hydrogen end runs δ+. Water is polar because of its shape — not because O–H (ΔEN 1.24) is somehow "more polar" than C=O (ΔEN 0.89). Both bonds are genuinely polar. The difference is entirely geometric.

The one idea to hold onto

Molecular polarity takes two inputs: how polar the bonds are (ΔEN), and where they point (shape). Polar bonds in a symmetric arrangement usually cancel — nonpolar molecule. Polar bonds in a lopsided arrangement don't — polar molecule. Skip either input and you'll get CO2 wrong, or water wrong, or both.

Watch the two-step check on methane. Then run it yourself on ammonia.

Same two questions every time: is the bond polar, and does the shape let those pulls cancel?

C H H H H symmetric pulls cancel nonpolar overall · LDF only N lone pair H H H pulls reinforce toward N polar overall · dipole-dipole + H-bonding
bond polarity + geometry = molecular polarity

Five molecules. Same two-step check every time.

Pick a molecule. Judge its bond, then judge what its shape does to that bond's pull. The verdict only appears after you've committed to both.

Cancel or reinforce? · pick a molecule
ΔEN
bond
Pick a molecule above to begin

Practice classifying molecular polarity

Test your understanding of bond polarity and shape. Sort each molecule into the correct category below.

Fill the blanks from memory.

Stuck on one? Tap Reveal. The point is pulling it from your head, not recognizing it on the page.

Electronegativity difference (ΔEN) tells you whether a single bond has a . Molecular shape decides whether those bond dipoles cancel or . A perfectly symmetric arrangement of polar bonds makes their pulls , giving a nonpolar molecule. A polar molecule picks up forces on top of the London dispersion forces every molecule has. Hydrogen bonding only switches on when hydrogen sits directly on nitrogen, oxygen, or .

Trace the whole chain before you write.

Shape → molecular polarity → IMF type → energy needed to separate molecules → physical state. The common shortcut — "water has O–H bonds, so it has hydrogen bonds" — gets the right answer for the wrong reason, and it'll fail you on the next molecule. Write out every link before you check.

Write your answer first. Then grade yourself.

Give yourself a point for each idea you actually wrote down. The flag (⚑) marks the move that separates a full-credit answer from a partial one.

Gen Chem · HS-PS1-2 · constructed response[4 marks]

Methane (CH4) boils at −162°C. Ammonia (NH3) boils at −33°C — about 130 degrees higher — even though the two molecules have nearly identical mass (16.05 vs. 17.04 g/mol). Construct the full argument for the difference: bonds → shape → molecular polarity → IMF → boiling point.

Mark scheme — 4 marks
  • States the bond polarities: C–H is essentially nonpolar (ΔEN = 0.35), while N–H is polar (ΔEN = 0.84).
  • Links shape to molecular polarity: CH4's symmetric shape cancels what little pull exists, while NH3's pyramidal shape makes its three N–H pulls reinforce into a net dipole. (⚑ This is the step everyone skips — the difference between describing bonds and explaining the molecule.)
  • Identifies the IMF difference: CH4 gets London dispersion forces only; NH3 gets dipole-dipole plus hydrogen bonding (H bonded directly to N).
  • Links to boiling point: stronger attractions between molecules take more thermal energy to break, so NH3 needs a much higher temperature to boil.

Self-score: 4 = all four · 3 = missing the shape→polarity link · 2 = bonds + IMF, no shape reasoning · ≤1 = boiling points restated only.

Why This Matters

Microwave ovens operate on molecular polarity. Microwaves cook food by emitting radiation that matches the natural rotational frequency of polar water molecules. The waves make the water's net dipoles spin rapidly, generating heat through friction, while nonpolar containers (like plastics) are left cold and unaffected.